A circuit that is 1,500 feet from the control unit to the last device using 18 AWG uncoated solid copper conductor will have a loop resistance of?

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Study for the Fire Alarm Lesson 5and6 Test. Prepare with flashcards and multiple choice questions; each question comes with hints and explanations. Gear up for success on your exam!

Multiple Choice

A circuit that is 1,500 feet from the control unit to the last device using 18 AWG uncoated solid copper conductor will have a loop resistance of?

Explanation:
The concept here is loop resistance, which is the total resistance along the path the signal travels from the control unit to the farthest device and back. In a loop circuit, current must go out to the last device and return, so you use the round-trip length. For 18 AWG bare copper, a commonly used resistance value in this context is about 7.77 ohms per 1,000 feet. The one-way distance is 1,500 feet, so the round-trip length is 3,000 feet. Converting to thousands of feet and multiplying: (3.0) × 7.77 Ω = 23.31 Ω. Therefore, the loop resistance is 23.31 ohms.

The concept here is loop resistance, which is the total resistance along the path the signal travels from the control unit to the farthest device and back. In a loop circuit, current must go out to the last device and return, so you use the round-trip length. For 18 AWG bare copper, a commonly used resistance value in this context is about 7.77 ohms per 1,000 feet. The one-way distance is 1,500 feet, so the round-trip length is 3,000 feet. Converting to thousands of feet and multiplying: (3.0) × 7.77 Ω = 23.31 Ω. Therefore, the loop resistance is 23.31 ohms.

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